如何用PHP根据特定字段实现数组的横向合并成长尾?

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本文共计565个文字,预计阅读时间需要3分钟。

如何用PHP根据特定字段实现数组的横向合并成长尾?

原文示例:本文字例讲述了PHP实现数组根据某个字段进行水平合并,纵向合并。分享给大众参考,具体如下:PHP数组水平合并,纵向合并,两条数据合并成一行。需求:将两个数组中日期相同的元素合并成一行。

本文实例讲述了PHP实现数组根据某个字段进行水平合并,横向合并。分享给大家供大家参考,具体如下:

PHP数组水平合并,横向合并,两条数据合并成一行

需求

将两个素组中日期相同的合并成一行

数组a

Array ( [0] => Array ( [date] => 2019-04-02 [today_pay_money] => 168.00 [today_pay_num] => 1 [yesterday_pay_money] => 999.00 [yesterday_pay_num] => 1 ) [1] => Array ( [date] => 2019-04-09 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 0.00 [yesterday_pay_num] => 0 ) [2] => Array ( [date] => 2019-05-05 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 2.00 [yesterday_pay_num] => 1 ) [3] => Array ( [date] => 2019-05-11 [today_pay_money] => 0.00 [today_pay_num] => 0 [yesterday_pay_money] => [yesterday_pay_num] => 1 ) )

数组B

Array ( [0] => Array ( [date] => 2019-05-07 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 0 [yesterday_pay_num1] => 0 ) [1] => Array ( [date] => 2019-05-11 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 1 [yesterday_pay_num1] => 1 ) )

需要格式

Array ( [2019-04-02] => Array ( [date] => 2019-04-02 [today_pay_money] => 168.00 [today_pay_num] => 1 [yesterday_pay_money] => 999.00 [yesterday_pay_num] => 1 ) [2019-04-09] => Array ( [date] => 2019-04-09 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 0.00 [yesterday_pay_num] => 0 ) [2019-05-05] => Array ( [date] => 2019-05-05 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 2.00 [yesterday_pay_num] => 1 ) [2019-05-11] => Array ( [date] => 2019-05-11 [today_pay_money] => 0.00 [today_pay_num] => 0 [yesterday_pay_money] => [yesterday_pay_num] => 1 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 1 [yesterday_pay_num1] => 1 ) [2019-05-07] => Array ( [date] => 2019-05-07 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 0 [yesterday_pay_num1] => 0 ) )

代码实现

先将a,b数组合并,判断当前日期下是否空,空的话直接赋值,不空的话,将已有素组和当前数组合并

$total = array_merge($a,$b)); $res = array(); foreach ($total as $k => $v) { if (empty($res[$v['date']])) $res[$v['date']] = $v; else $res[$v['date']]= array_merge($res[$v['date']],$v); }

更多关于PHP相关内容感兴趣的读者可查看本站专题:《PHP数组(Array)操作技巧大全》、《php排序算法总结》、《PHP数据结构与算法教程》、《php程序设计算法总结》、《php字符串(string)用法总结》及《PHP常用遍历算法与技巧总结》

希望本文所述对大家PHP程序设计有所帮助。

如何用PHP根据特定字段实现数组的横向合并成长尾?

本文共计565个文字,预计阅读时间需要3分钟。

如何用PHP根据特定字段实现数组的横向合并成长尾?

原文示例:本文字例讲述了PHP实现数组根据某个字段进行水平合并,纵向合并。分享给大众参考,具体如下:PHP数组水平合并,纵向合并,两条数据合并成一行。需求:将两个数组中日期相同的元素合并成一行。

本文实例讲述了PHP实现数组根据某个字段进行水平合并,横向合并。分享给大家供大家参考,具体如下:

PHP数组水平合并,横向合并,两条数据合并成一行

需求

将两个素组中日期相同的合并成一行

数组a

Array ( [0] => Array ( [date] => 2019-04-02 [today_pay_money] => 168.00 [today_pay_num] => 1 [yesterday_pay_money] => 999.00 [yesterday_pay_num] => 1 ) [1] => Array ( [date] => 2019-04-09 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 0.00 [yesterday_pay_num] => 0 ) [2] => Array ( [date] => 2019-05-05 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 2.00 [yesterday_pay_num] => 1 ) [3] => Array ( [date] => 2019-05-11 [today_pay_money] => 0.00 [today_pay_num] => 0 [yesterday_pay_money] => [yesterday_pay_num] => 1 ) )

数组B

Array ( [0] => Array ( [date] => 2019-05-07 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 0 [yesterday_pay_num1] => 0 ) [1] => Array ( [date] => 2019-05-11 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 1 [yesterday_pay_num1] => 1 ) )

需要格式

Array ( [2019-04-02] => Array ( [date] => 2019-04-02 [today_pay_money] => 168.00 [today_pay_num] => 1 [yesterday_pay_money] => 999.00 [yesterday_pay_num] => 1 ) [2019-04-09] => Array ( [date] => 2019-04-09 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 0.00 [yesterday_pay_num] => 0 ) [2019-05-05] => Array ( [date] => 2019-05-05 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 2.00 [yesterday_pay_num] => 1 ) [2019-05-11] => Array ( [date] => 2019-05-11 [today_pay_money] => 0.00 [today_pay_num] => 0 [yesterday_pay_money] => [yesterday_pay_num] => 1 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 1 [yesterday_pay_num1] => 1 ) [2019-05-07] => Array ( [date] => 2019-05-07 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 0 [yesterday_pay_num1] => 0 ) )

代码实现

先将a,b数组合并,判断当前日期下是否空,空的话直接赋值,不空的话,将已有素组和当前数组合并

$total = array_merge($a,$b)); $res = array(); foreach ($total as $k => $v) { if (empty($res[$v['date']])) $res[$v['date']] = $v; else $res[$v['date']]= array_merge($res[$v['date']],$v); }

更多关于PHP相关内容感兴趣的读者可查看本站专题:《PHP数组(Array)操作技巧大全》、《php排序算法总结》、《PHP数据结构与算法教程》、《php程序设计算法总结》、《php字符串(string)用法总结》及《PHP常用遍历算法与技巧总结》

希望本文所述对大家PHP程序设计有所帮助。

如何用PHP根据特定字段实现数组的横向合并成长尾?