如何通过stl set_difference函数准确判断车辆出入特定区域?
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本文共计414个文字,预计阅读时间需要2分钟。
核心代码如下:python示例代码def example_function(): # 这里是核心代码逻辑 pass
调用核心代码example_function()
核心代码
#include <iostream> #include <vector> #include <string> #include <algorithm> using namespace std; struct _AREA_VECTOR_STRUCT { int nAreaType;//区域类型 int nAreaID;//区域ID }; void CtestDlg::OnBnClickedButton2() { vector<_AREA_VECTOR_STRUCT> structAreaHistory;//车辆上一次所在区域 vector<_AREA_VECTOR_STRUCT> structAreaNow;//车辆本次所在区域 vector<_AREA_VECTOR_STRUCT> OutStructAreaVector;//输出区域 _AREA_VECTOR_STRUCT structVehicle; //模拟上一次车辆所在的区域集合 structVehicle.nAreaType = 2; structVehicle.nAreaID = 0x45; structAreaHistory.push_back(structVehicle); structVehicle.nAreaID = 0x7A; structAreaHistory.push_back(structVehicle); structVehicle.nAreaID = 0x88; structAreaHistory.push_back(structVehicle); structVehicle.nAreaType = 3; structVehicle.nAreaID = 0x55; structAreaHistory.push_back(structVehicle); structVehicle.nAreaID = 0x88; structAreaHistory.push_back(structVehicle); //模拟本次车辆所在的区域集合 structVehicle.nAreaType = 2; structVehicle.nAreaID = 0x88; structAreaNow.push_back(structVehicle); structVehicle.nAreaID = 0x45; structAreaNow.push_back(structVehicle); structVehicle.nAreaID = 0x11; structAreaNow.push_back(structVehicle); structVehicle.nAreaType = 3; structVehicle.nAreaID = 0x55; structAreaNow.push_back(structVehicle); //排序,先按区域类型排序,再按区域ID排序 sort(structAreaHistory.begin(), structAreaHistory.end(),[] (_AREA_VECTOR_STRUCT structArea1, _AREA_VECTOR_STRUCT structArea2)->bool { if(structArea1.nAreaType != structArea2.nAreaType) return structArea1.nAreaType < structArea2.nAreaType; else return structArea1.nAreaID < structArea2.nAreaID; }); sort(structAreaNow.begin(), structAreaNow.end(),[] (_AREA_VECTOR_STRUCT structArea1, _AREA_VECTOR_STRUCT structArea2)->bool { if(structArea1.nAreaType != structArea2.nAreaType) return structArea1.nAreaType < structArea2.nAreaType; else return structArea1.nAreaID < structArea2.nAreaID; }); int a = 0; //求差,结果为离开区域的集合(出区域) set_difference(structAreaHistory.begin(), structAreaHistory.end(), structAreaNow.begin(), structAreaNow.end(), back_inserter(OutStructAreaVector), [](_AREA_VECTOR_STRUCT structArea1, _AREA_VECTOR_STRUCT structArea2)->bool { if(structArea1.nAreaType != structArea2.nAreaType) return structArea1.nAreaType < structArea2.nAreaType; else return structArea1.nAreaID < structArea2.nAreaID; }); if(OutStructAreaVector.size() != 0) { TRACE("出"); } OutStructAreaVector.clear();//先清空 //反过来求差,结果为新进入的区域集合(新进区域) set_difference(structAreaNow.begin(), structAreaNow.end(), structAreaHistory.begin(), structAreaHistory.end(), back_inserter(OutStructAreaVector), [](_AREA_VECTOR_STRUCT structArea1, _AREA_VECTOR_STRUCT structArea2)->bool { if(structArea1.nAreaType != structArea2.nAreaType) return structArea1.nAreaType < structArea2.nAreaType; else return structArea1.nAreaID < structArea2.nAreaID; }); if(OutStructAreaVector.size() != 0) { TRACE("重新进"); } }
本文共计414个文字,预计阅读时间需要2分钟。
核心代码如下:python示例代码def example_function(): # 这里是核心代码逻辑 pass
调用核心代码example_function()
核心代码
#include <iostream> #include <vector> #include <string> #include <algorithm> using namespace std; struct _AREA_VECTOR_STRUCT { int nAreaType;//区域类型 int nAreaID;//区域ID }; void CtestDlg::OnBnClickedButton2() { vector<_AREA_VECTOR_STRUCT> structAreaHistory;//车辆上一次所在区域 vector<_AREA_VECTOR_STRUCT> structAreaNow;//车辆本次所在区域 vector<_AREA_VECTOR_STRUCT> OutStructAreaVector;//输出区域 _AREA_VECTOR_STRUCT structVehicle; //模拟上一次车辆所在的区域集合 structVehicle.nAreaType = 2; structVehicle.nAreaID = 0x45; structAreaHistory.push_back(structVehicle); structVehicle.nAreaID = 0x7A; structAreaHistory.push_back(structVehicle); structVehicle.nAreaID = 0x88; structAreaHistory.push_back(structVehicle); structVehicle.nAreaType = 3; structVehicle.nAreaID = 0x55; structAreaHistory.push_back(structVehicle); structVehicle.nAreaID = 0x88; structAreaHistory.push_back(structVehicle); //模拟本次车辆所在的区域集合 structVehicle.nAreaType = 2; structVehicle.nAreaID = 0x88; structAreaNow.push_back(structVehicle); structVehicle.nAreaID = 0x45; structAreaNow.push_back(structVehicle); structVehicle.nAreaID = 0x11; structAreaNow.push_back(structVehicle); structVehicle.nAreaType = 3; structVehicle.nAreaID = 0x55; structAreaNow.push_back(structVehicle); //排序,先按区域类型排序,再按区域ID排序 sort(structAreaHistory.begin(), structAreaHistory.end(),[] (_AREA_VECTOR_STRUCT structArea1, _AREA_VECTOR_STRUCT structArea2)->bool { if(structArea1.nAreaType != structArea2.nAreaType) return structArea1.nAreaType < structArea2.nAreaType; else return structArea1.nAreaID < structArea2.nAreaID; }); sort(structAreaNow.begin(), structAreaNow.end(),[] (_AREA_VECTOR_STRUCT structArea1, _AREA_VECTOR_STRUCT structArea2)->bool { if(structArea1.nAreaType != structArea2.nAreaType) return structArea1.nAreaType < structArea2.nAreaType; else return structArea1.nAreaID < structArea2.nAreaID; }); int a = 0; //求差,结果为离开区域的集合(出区域) set_difference(structAreaHistory.begin(), structAreaHistory.end(), structAreaNow.begin(), structAreaNow.end(), back_inserter(OutStructAreaVector), [](_AREA_VECTOR_STRUCT structArea1, _AREA_VECTOR_STRUCT structArea2)->bool { if(structArea1.nAreaType != structArea2.nAreaType) return structArea1.nAreaType < structArea2.nAreaType; else return structArea1.nAreaID < structArea2.nAreaID; }); if(OutStructAreaVector.size() != 0) { TRACE("出"); } OutStructAreaVector.clear();//先清空 //反过来求差,结果为新进入的区域集合(新进区域) set_difference(structAreaNow.begin(), structAreaNow.end(), structAreaHistory.begin(), structAreaHistory.end(), back_inserter(OutStructAreaVector), [](_AREA_VECTOR_STRUCT structArea1, _AREA_VECTOR_STRUCT structArea2)->bool { if(structArea1.nAreaType != structArea2.nAreaType) return structArea1.nAreaType < structArea2.nAreaType; else return structArea1.nAreaID < structArea2.nAreaID; }); if(OutStructAreaVector.size() != 0) { TRACE("重新进"); } }

