Python3如何实现查找列表中重复元素个数的三种高效方法？

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方法一：使用集合pythonmylist=[1, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 4]myset=set(mylist)for item in myset: print(fthe {item} has found {mylist.count(item)})

方法二：使用collections模块pythonfrom collections import Counter

mylist=[1, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 4]counter=Counter(mylist)for item, count in counter.items(): print(fthe {item} has found {count})

方法一：

mylist = [1,2,2,2,2,3,3,3,4,4,4,4] myset = set(mylist) for item in myset: print("the %d has found %d" %(item,mylist.count(item)))

the 1 has found 1

the 2 has found 4

the 3 has found 3

the 4 has found 4

方法二：

from collections import Counter Counter([1,2,2,2,2,3,3,3,4,4,4,4]) Counter({2: 4, 4: 4, 3: 3, 1: 1})

方法三：

List=[1,2,2,2,2,3,3,3,4,4,4,4] a = {} for i in List: if List.count(i)>1: a[i] = List.count(i)

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