如何将图片进行精确的Crop Image操作?

2026-04-06 12:100阅读0评论SEO问题
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本文共计105个文字,预计阅读时间需要1分钟。

如何将图片进行精确的Crop Image操作?

pythondef crop(cropW, cropH, w, h): k1=cropW / w k2=cropH / h k=k1 + k2 if k1 > k2 else k2 fitW=math.ceil(w * k)

gistfile1.txt

/** * cropW, cropH: width and height to be cropped * w, h: width and height of source image */ function crop(cropW, cropH, w, h) { let k1 = cropW / w; let k2 = cropH / h; let k = k1 > k2 ? k1 : k2; let fitW = Math.ceil(w * k); let fitH = Math.ceil(h * k); let topLeftX = Math.ceil((fitW - cropW) / 2); let topLeftY = Math.ceil((fitH - cropH) / 2); console.info('fit wxh:' + fitW + 'x' + fitH + ' crop from (' + topLeftX + ',' + topLeftY + ')'); }

如何将图片进行精确的Crop Image操作?

本文共计105个文字,预计阅读时间需要1分钟。

如何将图片进行精确的Crop Image操作?

pythondef crop(cropW, cropH, w, h): k1=cropW / w k2=cropH / h k=k1 + k2 if k1 > k2 else k2 fitW=math.ceil(w * k)

gistfile1.txt

/** * cropW, cropH: width and height to be cropped * w, h: width and height of source image */ function crop(cropW, cropH, w, h) { let k1 = cropW / w; let k2 = cropH / h; let k = k1 > k2 ? k1 : k2; let fitW = Math.ceil(w * k); let fitH = Math.ceil(h * k); let topLeftX = Math.ceil((fitW - cropW) / 2); let topLeftY = Math.ceil((fitH - cropH) / 2); console.info('fit wxh:' + fitW + 'x' + fitH + ' crop from (' + topLeftX + ',' + topLeftY + ')'); }

如何将图片进行精确的Crop Image操作?