如何将非线性参数的函数定义方式转化为长尾词?

2026-04-06 19:271阅读0评论SEO问题
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本文共计154个文字,预计阅读时间需要1分钟。

如何将非线性参数的函数定义方式转化为长尾词?

javascriptfun.jslet fun=function(a, b, c, d) { let options={a: 1, b: 'a', c: {}, d: function(a, b, c) {}}; let isUndefined=typeof o==='undefined'; let isFunction=typeof o==='function'; let isNumber=typeof o==='number';};

如何将非线性参数的函数定义方式转化为长尾词?

fun.js

let fun = function ( a, b, c, d) { let options = { a: 1, b: 'a', c: {}, d: function ( a, b, c) {} }; let isUndefined = o => typeof o == 'undefined'; let isFunction = o => typeof o == 'function'; let isNumber = o => typeof o == 'number'; let isString = o => typeof o == 'string'; let isObject = o => typeof o == 'object'; let setOptions = function ( o) { if ( isNumber( o)) { options.a = o; } else if ( isString( o)) { options.b = o; } else if ( isObject( o)) { options.c = o; } else if ( isFunction( o)) { options.d = o; } } for ( let obj of arguments) { setOptions( obj); } options.d( options.a, options.b, options.c); } fun( ( a, b, c) => { console.log( a, b, c); }, { list:[]}, 3, 'b');

本文共计154个文字,预计阅读时间需要1分钟。

如何将非线性参数的函数定义方式转化为长尾词?

javascriptfun.jslet fun=function(a, b, c, d) { let options={a: 1, b: 'a', c: {}, d: function(a, b, c) {}}; let isUndefined=typeof o==='undefined'; let isFunction=typeof o==='function'; let isNumber=typeof o==='number';};

如何将非线性参数的函数定义方式转化为长尾词?

fun.js

let fun = function ( a, b, c, d) { let options = { a: 1, b: 'a', c: {}, d: function ( a, b, c) {} }; let isUndefined = o => typeof o == 'undefined'; let isFunction = o => typeof o == 'function'; let isNumber = o => typeof o == 'number'; let isString = o => typeof o == 'string'; let isObject = o => typeof o == 'object'; let setOptions = function ( o) { if ( isNumber( o)) { options.a = o; } else if ( isString( o)) { options.b = o; } else if ( isObject( o)) { options.c = o; } else if ( isFunction( o)) { options.d = o; } } for ( let obj of arguments) { setOptions( obj); } options.d( options.a, options.b, options.c); } fun( ( a, b, c) => { console.log( a, b, c); }, { list:[]}, 3, 'b');