Unity3D中如何创建基于网格功能的球形网格模型？

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本文以Unity3D为例，分享了如何使用网格功能生成球体网格模型的代码示例。具体内容如下：

1. 首先，介绍如何使用mesh生成自定义网格。

2.接着，讲解如何将这个网格变换为球体网格。

具体代码如下：

csharp

using UnityEngine;

public class SphereMeshGenerator : MonoBehaviour{ void Start() { Mesh mesh=new Mesh(); GenerateSphereMesh(mesh); GetComponent().mesh=mesh; }

void GenerateSphereMesh(Mesh mesh) { // 球体的半径 float radius=1.0f; // 球体的细分程度 int segments=10;

// 球体的顶点数 int vertexCount=(segments + 1) * (segments + 1); Vector3[] vertices=new Vector3[vertexCount];

// 球体的索引数 int indexCount=segments * segments * 6; int[] indices=new int[indexCount];

// 生成球体的顶点 for (int i=0; i <=segments; i++) { for (int j=0; j <=segments; j++) { float u=(float)i / segments; float v=(float)j / segments;

vertices[i * (segments + 1) + j]=new Vector3(radius * Mathf.Cos(u * Mathf.PI * 2) * Mathf.Sin(v * Mathf.PI * 2), radius * Mathf.Sin(u * Mathf.PI * 2) * Mathf.Sin(v * Mathf.PI * 2), radius * Mathf.Cos(v * Mathf.PI * 2)); } }

// 生成球体的索引 for (int i=0; i

indices[i * segments * 6 + j * 6]=vi; indices[i * segments * 6 + j * 6 + 1]=vj; indices[i * segments * 6 + j * 6 + 2]=vk;

indices[i * segments * 6 + j * 6 + 3]=vk; indices[i * segments * 6 + j * 6 + 4]=vl; indices[i * segments * 6 + j * 6 + 5]=vi; } }

// 设置网格的顶点和索引 mesh.vertices=vertices; mesh.triangles=indices; }}

通过以上代码，我们可以生成一个球体网格模型。

本文实例为大家分享了Unity3D网格功能生成球体网格模型的具体代码，供大家参考，具体内容如下

前面已经讲过怎样使用mesh生成一个自己的网格，那么本文将会讲述怎样将这个网格变换成自己想要的形状，比如一个球体。

我们需要知道一个从平面坐标到球体坐标的映射公式。假设平面坐标是（x，y），球体坐标是（x0，y0，z0），则

球体坐标（x0，y0，z0）可以通过以下代码得到，（x，y） 对应vertices[i].x和vertices[i].y。

v.x = r * Mathf.Cos(vertices[i].x / width * 2 * Mathf.PI) * Mathf.Cos(vertices[i].y / height * Mathf.PI - Mathf.PI / 2); v.y = r * Mathf.Sin(vertices[i].x / width * 2 * Mathf.PI) * Mathf.Cos(vertices[i].y / height * Mathf.PI - Mathf.PI / 2); v.z = r * Mathf.Sin(vertices[i].y / height * Mathf.PI - Mathf.PI / 2);

完整代码在最后，将完整的脚本绑定到一个空物体上，把棋盘格图案chessboard.jpg放到Assets\Resources下，还要在场景中生成一个sphere作为显示网格顶点的辅助物体。一切就绪后，运行效果如下：

using UnityEngine; using System.Collections; public class BallMesh : MonoBehaviour { Mesh mesh; Vector3[] vertices; Vector2[] uv; int[] triangles; Vector3[] normals; public GameObject sphere; GameObject[] spheres; void Start() { gameObject.AddComponent<MeshFilter>(); gameObject.AddComponent<MeshRenderer>(); Texture img = (Texture)Resources.Load("tm"); gameObject.GetComponent<Renderer>().material.mainTexture = img; mesh = new Mesh(); int m = 25; //row int n = 50; //col float width = 8; float height = 6; vertices = new Vector3[(m + 1) * (n + 1)];//the positions of vertices spheres = new GameObject[(m + 1) * (n + 1)]; uv = new Vector2[(m + 1) * (n + 1)]; normals = new Vector3[(m + 1) * (n + 1)]; triangles = new int[6 * m * n]; for (int i = 0; i < vertices.Length; i++) { float x = i % (n + 1); float y = i / (n + 1); float x_pos = x / n * width; float y_pos = y / m * height; vertices[i] = new Vector3(x_pos, y_pos, 0); float u = x / n; float v = y / m; uv[i] = new Vector2(u, v); } for (int i = 0; i < 2 * m * n; i++) { int[] triIndex = new int[3]; if (i % 2 == 0) { triIndex[0] = i / 2 + i / (2 * n); triIndex[1] = triIndex[0] + 1; triIndex[2] = triIndex[0] + (n + 1); } else { triIndex[0] = (i + 1) / 2 + i / (2 * n); triIndex[1] = triIndex[0] + (n + 1); triIndex[2] = triIndex[1] - 1; } triangles[i * 3] = triIndex[0]; triangles[i * 3 + 1] = triIndex[1]; triangles[i * 3 + 2] = triIndex[2]; } int r = 10; for (int i = 0; i < vertices.Length; i++) { spheres[i] = Instantiate( sphere,this.transform) as GameObject; Vector3 v ; v.x = r * Mathf.Cos(vertices[i].x / width * 2 * Mathf.PI) * Mathf.Cos(vertices[i].y / height * Mathf.PI - Mathf.PI / 2); v.y = r * Mathf.Sin(vertices[i].x / width * 2 * Mathf.PI) * Mathf.Cos(vertices[i].y / height * Mathf.PI - Mathf.PI / 2); v.z = r * Mathf.Sin(vertices[i].y / height * Mathf.PI - Mathf.PI / 2); //v = vertices[i]; vertices[i] = v; spheres[i].transform.localPosition = v; normals[i] = new Vector3(0,1,0); } mesh.vertices = vertices; mesh.normals = normals; mesh.uv = uv; mesh.triangles = triangles; this.GetComponent<MeshFilter>().mesh = mesh; } }

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持易盾网络。