如何将Python字典转换成有序字典？

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1. 使用`OrderedDict`，如果当前文件是主程序：pythonfrom collections import OrderedDictcolumns={column_1: value1, column_3: value3, column_2: value2, column_5: value5, column_4: value4}new_dict=OrderedDict(columns)

1. 使用OrderedDict

if __name__ == "__main__":
from collections import OrderedDict
columns = {"column_1": "value1", "column_3": "value3","column_2": "value2","column_5": "value5","column_4": "value4"}
new_dict = OrderedDict(sorted(columns.items(), key=lambda x: int(x[0].split("_")[1])))
print(new_dict)

# 输出的结果为
{"column_1": "value1", "column_2": "value2","column_3": "value3","column_4": "value4","column_5": "value5"}

2. 添加时顺序保存

```python
if __name__ == "__main__":
import collections
old_dict = collections.OrderedDict()
old_dict["column_1"] = "value1"
old_dict["column_2"] = "value2"
old_dict["column_3"] = "value3"
old_dict["column_4"] = "value4"
old_dict["column_5"] = "value5"
print(old_dict)

# 输出的结果为
{"column_1": "value1", "column_2": "value2","column_3": "value3","column_4": "value4","column_5": "value5"}