蓝桥杯Python组中,如何编写递增序列的代码?
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本文共计781个文字,预计阅读时间需要4分钟。
蓝桥杯Python组——递增序列 + 题目描述:本题要求填充空白题,只需算出结果后,在代码中使用输出语句将所填结果输出即可。对于一个字母矩阵,我们称矩阵中的某一行或某一列的元素依次递增为递增序列。题目要求找出矩阵中所有递增序列的长度。
代码示例:pythondef find_increasing_sequences(matrix): rows=len(matrix) cols=len(matrix[0]) sequences=[]
for i in range(rows): for j in range(cols): if is_increasing(matrix, i, j): sequences.append(len(get_increasing_sequence(matrix, i, j)))
return sequences
def is_increasing(matrix, row, col): row_len=len(matrix[row]) col_len=len(matrix[0]) for k in range(1, row_len): if matrix[row][col + k] !=chr(ord(matrix[row][col]) + k): return False for k in range(1, col_len): if matrix[row + k][col] !=chr(ord(matrix[row][col]) + k): return False return True
def get_increasing_sequence(matrix, row, col): sequence=[] rows=len(matrix) cols=len(matrix[0]) for i in range(row, rows): for j in range(col, cols): sequence.append(matrix[i][j]) if len(sequence)==rows: break if matrix[i + 1][j] !=chr(ord(matrix[i][j]) + 1): break return sequence
示例矩阵matrix=[ ['a', 'b', 'c', 'd'], ['b', 'c', 'd', 'e'], ['c', 'd', 'e', 'f'], ['d', 'e', 'f', 'g']]
输出递增序列长度print(find_increasing_sequences(matrix))
蓝桥杯python组——递增序列
题目描述
本题为填空题,只需要算出结果后,在代码中使用输出语句将所填结果输出即可。对于一个字母矩阵,我们称矩阵中的一个递增序列是指在矩阵中找到两个字母,它们在同一行,同一列,或者在同一 4545 度的斜线上,这两个字母从左向右看、或者从上向下看是递增的。
例如,如下矩阵中
有LN、LN、AN、AN、IO、AO、LQ、AI、NO、NO、AQ、IN、AN 等 13 个 递增序列。注意当两个字母是从左下到右上排列时,从左向右看和从上向下看 是不同的顺序。
对于下面的 30行 50 列的矩阵,请问总共有多少个递增序列?
VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAGSDLLOVGRTWEYZKKXNKIRWGZWXWRHKXFASATDWZAPZRNHTNNGQF
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ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXXdata = ["VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAG",\
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"BMQGMPDRCPGWKTPLOTAINXZAAJWCPUJHPOUYWNWHZAKCDMZDSR",\
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"ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXX"]
ans = 0
for i in range(0,30):
for j in range(0,50):
for x in range(0,30):
for y in range(0,50):
if data[i][j] < data[x][y] and ((i == x and y > j) or (j == y and x > i) or (abs(y - j) == abs(x - i) and not (x <= i and y <= j))):
ans += 1
print(ans)
答案为52800
谢谢大家的支持,您的一键三连是 罡罡同学前进的最大动力!
本文共计781个文字,预计阅读时间需要4分钟。
蓝桥杯Python组——递增序列 + 题目描述:本题要求填充空白题,只需算出结果后,在代码中使用输出语句将所填结果输出即可。对于一个字母矩阵,我们称矩阵中的某一行或某一列的元素依次递增为递增序列。题目要求找出矩阵中所有递增序列的长度。
代码示例:pythondef find_increasing_sequences(matrix): rows=len(matrix) cols=len(matrix[0]) sequences=[]
for i in range(rows): for j in range(cols): if is_increasing(matrix, i, j): sequences.append(len(get_increasing_sequence(matrix, i, j)))
return sequences
def is_increasing(matrix, row, col): row_len=len(matrix[row]) col_len=len(matrix[0]) for k in range(1, row_len): if matrix[row][col + k] !=chr(ord(matrix[row][col]) + k): return False for k in range(1, col_len): if matrix[row + k][col] !=chr(ord(matrix[row][col]) + k): return False return True
def get_increasing_sequence(matrix, row, col): sequence=[] rows=len(matrix) cols=len(matrix[0]) for i in range(row, rows): for j in range(col, cols): sequence.append(matrix[i][j]) if len(sequence)==rows: break if matrix[i + 1][j] !=chr(ord(matrix[i][j]) + 1): break return sequence
示例矩阵matrix=[ ['a', 'b', 'c', 'd'], ['b', 'c', 'd', 'e'], ['c', 'd', 'e', 'f'], ['d', 'e', 'f', 'g']]
输出递增序列长度print(find_increasing_sequences(matrix))
蓝桥杯python组——递增序列
题目描述
本题为填空题,只需要算出结果后,在代码中使用输出语句将所填结果输出即可。对于一个字母矩阵,我们称矩阵中的一个递增序列是指在矩阵中找到两个字母,它们在同一行,同一列,或者在同一 4545 度的斜线上,这两个字母从左向右看、或者从上向下看是递增的。
例如,如下矩阵中
有LN、LN、AN、AN、IO、AO、LQ、AI、NO、NO、AQ、IN、AN 等 13 个 递增序列。注意当两个字母是从左下到右上排列时,从左向右看和从上向下看 是不同的顺序。
对于下面的 30行 50 列的矩阵,请问总共有多少个递增序列?
VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAGSDLLOVGRTWEYZKKXNKIRWGZWXWRHKXFASATDWZAPZRNHTNNGQF
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BMQGMPDRCPGWKTPLOTAINXZAAJWCPUJHPOUYWNWHZAKCDMZDSR
RRARTVHZYYCEDXJQNQAINQVDJCZCZLCQWQQIKUYMYMOVMNCBVY
ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXXdata = ["VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAG",\
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"BMQGMPDRCPGWKTPLOTAINXZAAJWCPUJHPOUYWNWHZAKCDMZDSR",\
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"ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXX"]
ans = 0
for i in range(0,30):
for j in range(0,50):
for x in range(0,30):
for y in range(0,50):
if data[i][j] < data[x][y] and ((i == x and y > j) or (j == y and x > i) or (abs(y - j) == abs(x - i) and not (x <= i and y <= j))):
ans += 1
print(ans)
答案为52800
谢谢大家的支持,您的一键三连是 罡罡同学前进的最大动力!

