蓝桥杯Python组中,如何编写递增序列的代码?

2026-05-26 18:291阅读0评论SEO问题
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本文共计781个文字,预计阅读时间需要4分钟。

蓝桥杯Python组中,如何编写递增序列的代码?

蓝桥杯Python组——递增序列 + 题目描述:本题要求填充空白题,只需算出结果后,在代码中使用输出语句将所填结果输出即可。对于一个字母矩阵,我们称矩阵中的某一行或某一列的元素依次递增为递增序列。题目要求找出矩阵中所有递增序列的长度。

代码示例:pythondef find_increasing_sequences(matrix): rows=len(matrix) cols=len(matrix[0]) sequences=[]

for i in range(rows): for j in range(cols): if is_increasing(matrix, i, j): sequences.append(len(get_increasing_sequence(matrix, i, j)))

蓝桥杯Python组中,如何编写递增序列的代码?

return sequences

def is_increasing(matrix, row, col): row_len=len(matrix[row]) col_len=len(matrix[0]) for k in range(1, row_len): if matrix[row][col + k] !=chr(ord(matrix[row][col]) + k): return False for k in range(1, col_len): if matrix[row + k][col] !=chr(ord(matrix[row][col]) + k): return False return True

def get_increasing_sequence(matrix, row, col): sequence=[] rows=len(matrix) cols=len(matrix[0]) for i in range(row, rows): for j in range(col, cols): sequence.append(matrix[i][j]) if len(sequence)==rows: break if matrix[i + 1][j] !=chr(ord(matrix[i][j]) + 1): break return sequence

示例矩阵matrix=[ ['a', 'b', 'c', 'd'], ['b', 'c', 'd', 'e'], ['c', 'd', 'e', 'f'], ['d', 'e', 'f', 'g']]

输出递增序列长度print(find_increasing_sequences(matrix))


蓝桥杯python组——递增序列

题目描述

本题为填空题,只需要算出结果后,在代码中使用输出语句将所填结果输出即可。对于一个字母矩阵,我们称矩阵中的一个递增序列是指在矩阵中找到两个字母,它们在同一行,同一列,或者在同一 4545 度的斜线上,这两个字母从左向右看、或者从上向下看是递增的。

例如,如下矩阵中

有LN、LN、AN、AN、IO、AO、LQ、AI、NO、NO、AQ、IN、AN 等 13 个 递增序列。注意当两个字母是从左下到右上排列时,从左向右看和从上向下看 是不同的顺序。

对于下面的 30行 50 列的矩阵,请问总共有多少个递增序列?

VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAG
SDLLOVGRTWEYZKKXNKIRWGZWXWRHKXFASATDWZAPZRNHTNNGQF
ZGUGXVQDQAEAHOQEADMWWXFBXECKAVIGPTKTTQFWSWPKRPSMGA
BDGMGYHAOPPRRHKYZCMFZEDELCALTBSWNTAODXYVHQNDASUFRL
YVYWQZUTEPFSFXLTZBMBQETXGXFUEBHGMJKBPNIHMYOELYZIKH
ZYZHSLTCGNANNXTUJGBYKUOJMGOGRDPKEUGVHNZJZHDUNRERBU
XFPTZKTPVQPJEMBHNTUBSMIYEGXNWQSBZMHMDRZZMJPZQTCWLR
ZNXOKBITTPSHEXWHZXFLWEMPZTBVNKNYSHCIQRIKQHFRAYWOPG
MHJKFYYBQSDPOVJICWWGGCOZSBGLSOXOFDAADZYEOBKDDTMQPA
VIDPIGELBYMEVQLASLQRUKMXSEWGHRSFVXOMHSJWWXHIBCGVIF
GWRFRFLHAMYWYZOIQODBIHHRIIMWJWJGYPFAHZZWJKRGOISUJC
EKQKKPNEYCBWOQHTYFHHQZRLFNDOVXTWASSQWXKBIVTKTUIASK
PEKNJFIVBKOZUEPPHIWLUBFUDWPIDRJKAZVJKPBRHCRMGNMFWW
CGZAXHXPDELTACGUWBXWNNZNDQYYCIQRJCULIEBQBLLMJEUSZP
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PFGAYBDEECHUXFUZIKAXYDFWJNSAOPJYWUIEJSCORRBVQHCHMR
JNVIPVEMQSHCCAXMWEFSYIGFPIXNIDXOTXTNBCHSHUZGKXFECL
YZBAIIOTWLREPZISBGJLQDALKZUKEQMKLDIPXJEPENEIPWFDLP
HBQKWJFLSEXVILKYPNSWUZLDCRTAYUUPEITQJEITZRQMMAQNLN
DQDJGOWMBFKAIGWEAJOISPFPLULIWVVALLIIHBGEZLGRHRCKGF
LXYPCVPNUKSWCCGXEYTEBAWRLWDWNHHNNNWQNIIBUCGUJYMRYW
CZDKISKUSBPFHVGSAVJBDMNPSDKFRXVVPLVAQUGVUJEXSZFGFQ
IYIJGISUANRAXTGQLAVFMQTICKQAHLEBGHAVOVVPEXIMLFWIYI
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HGTEEIISFGIUEUOWXVTPJDVACYQYFQUCXOXOSSMXLZDQESHXKP
FEBZHJAGIFGXSMRDKGONGELOALLSYDVILRWAPXXBPOOSWZNEAS
VJGMAOFLGYIFLJTEKDNIWHJAABCASFMAKIENSYIZZSLRSUIPCJ
BMQGMPDRCPGWKTPLOTAINXZAAJWCPUJHPOUYWNWHZAKCDMZDSR
RRARTVHZYYCEDXJQNQAINQVDJCZCZLCQWQQIKUYMYMOVMNCBVY
ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXXdata = ["VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAG",\
"SDLLOVGRTWEYZKKXNKIRWGZWXWRHKXFASATDWZAPZRNHTNNGQF",\
"ZGUGXVQDQAEAHOQEADMWWXFBXECKAVIGPTKTTQFWSWPKRPSMGA",\
"BDGMGYHAOPPRRHKYZCMFZEDELCALTBSWNTAODXYVHQNDASUFRL",\
"YVYWQZUTEPFSFXLTZBMBQETXGXFUEBHGMJKBPNIHMYOELYZIKH",\
"ZYZHSLTCGNANNXTUJGBYKUOJMGOGRDPKEUGVHNZJZHDUNRERBU",\
"XFPTZKTPVQPJEMBHNTUBSMIYEGXNWQSBZMHMDRZZMJPZQTCWLR",\
"ZNXOKBITTPSHEXWHZXFLWEMPZTBVNKNYSHCIQRIKQHFRAYWOPG",\
"MHJKFYYBQSDPOVJICWWGGCOZSBGLSOXOFDAADZYEOBKDDTMQPA",\
"VIDPIGELBYMEVQLASLQRUKMXSEWGHRSFVXOMHSJWWXHIBCGVIF",\
"GWRFRFLHAMYWYZOIQODBIHHRIIMWJWJGYPFAHZZWJKRGOISUJC",\
"EKQKKPNEYCBWOQHTYFHHQZRLFNDOVXTWASSQWXKBIVTKTUIASK",\
"PEKNJFIVBKOZUEPPHIWLUBFUDWPIDRJKAZVJKPBRHCRMGNMFWW",\
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"DQDJGOWMBFKAIGWEAJOISPFPLULIWVVALLIIHBGEZLGRHRCKGF",\
"LXYPCVPNUKSWCCGXEYTEBAWRLWDWNHHNNNWQNIIBUCGUJYMRYW",\
"CZDKISKUSBPFHVGSAVJBDMNPSDKFRXVVPLVAQUGVUJEXSZFGFQ",\
"IYIJGISUANRAXTGQLAVFMQTICKQAHLEBGHAVOVVPEXIMLFWIYI",\
"ZIIFSOPCMAWCBPKWZBUQPQLGSNIBFADUUJJHPAIUVVNWNWKDZB",\
"HGTEEIISFGIUEUOWXVTPJDVACYQYFQUCXOXOSSMXLZDQESHXKP",\
"FEBZHJAGIFGXSMRDKGONGELOALLSYDVILRWAPXXBPOOSWZNEAS",\
"VJGMAOFLGYIFLJTEKDNIWHJAABCASFMAKIENSYIZZSLRSUIPCJ",\
"BMQGMPDRCPGWKTPLOTAINXZAAJWCPUJHPOUYWNWHZAKCDMZDSR",\
"RRARTVHZYYCEDXJQNQAINQVDJCZCZLCQWQQIKUYMYMOVMNCBVY",\
"ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXX"]

ans = 0
for i in range(0,30):
for j in range(0,50):
for x in range(0,30):
for y in range(0,50):
if data[i][j] < data[x][y] and ((i == x and y > j) or (j == y and x > i) or (abs(y - j) == abs(x - i) and not (x <= i and y <= j))):
ans += 1
print(ans)

答案为52800

谢谢大家的支持,您的一键三连是 罡罡同学前进的最大动力!



本文共计781个文字,预计阅读时间需要4分钟。

蓝桥杯Python组中,如何编写递增序列的代码?

蓝桥杯Python组——递增序列 + 题目描述:本题要求填充空白题,只需算出结果后,在代码中使用输出语句将所填结果输出即可。对于一个字母矩阵,我们称矩阵中的某一行或某一列的元素依次递增为递增序列。题目要求找出矩阵中所有递增序列的长度。

代码示例:pythondef find_increasing_sequences(matrix): rows=len(matrix) cols=len(matrix[0]) sequences=[]

for i in range(rows): for j in range(cols): if is_increasing(matrix, i, j): sequences.append(len(get_increasing_sequence(matrix, i, j)))

蓝桥杯Python组中,如何编写递增序列的代码?

return sequences

def is_increasing(matrix, row, col): row_len=len(matrix[row]) col_len=len(matrix[0]) for k in range(1, row_len): if matrix[row][col + k] !=chr(ord(matrix[row][col]) + k): return False for k in range(1, col_len): if matrix[row + k][col] !=chr(ord(matrix[row][col]) + k): return False return True

def get_increasing_sequence(matrix, row, col): sequence=[] rows=len(matrix) cols=len(matrix[0]) for i in range(row, rows): for j in range(col, cols): sequence.append(matrix[i][j]) if len(sequence)==rows: break if matrix[i + 1][j] !=chr(ord(matrix[i][j]) + 1): break return sequence

示例矩阵matrix=[ ['a', 'b', 'c', 'd'], ['b', 'c', 'd', 'e'], ['c', 'd', 'e', 'f'], ['d', 'e', 'f', 'g']]

输出递增序列长度print(find_increasing_sequences(matrix))


蓝桥杯python组——递增序列

题目描述

本题为填空题,只需要算出结果后,在代码中使用输出语句将所填结果输出即可。对于一个字母矩阵,我们称矩阵中的一个递增序列是指在矩阵中找到两个字母,它们在同一行,同一列,或者在同一 4545 度的斜线上,这两个字母从左向右看、或者从上向下看是递增的。

例如,如下矩阵中

有LN、LN、AN、AN、IO、AO、LQ、AI、NO、NO、AQ、IN、AN 等 13 个 递增序列。注意当两个字母是从左下到右上排列时,从左向右看和从上向下看 是不同的顺序。

对于下面的 30行 50 列的矩阵,请问总共有多少个递增序列?

VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAG
SDLLOVGRTWEYZKKXNKIRWGZWXWRHKXFASATDWZAPZRNHTNNGQF
ZGUGXVQDQAEAHOQEADMWWXFBXECKAVIGPTKTTQFWSWPKRPSMGA
BDGMGYHAOPPRRHKYZCMFZEDELCALTBSWNTAODXYVHQNDASUFRL
YVYWQZUTEPFSFXLTZBMBQETXGXFUEBHGMJKBPNIHMYOELYZIKH
ZYZHSLTCGNANNXTUJGBYKUOJMGOGRDPKEUGVHNZJZHDUNRERBU
XFPTZKTPVQPJEMBHNTUBSMIYEGXNWQSBZMHMDRZZMJPZQTCWLR
ZNXOKBITTPSHEXWHZXFLWEMPZTBVNKNYSHCIQRIKQHFRAYWOPG
MHJKFYYBQSDPOVJICWWGGCOZSBGLSOXOFDAADZYEOBKDDTMQPA
VIDPIGELBYMEVQLASLQRUKMXSEWGHRSFVXOMHSJWWXHIBCGVIF
GWRFRFLHAMYWYZOIQODBIHHRIIMWJWJGYPFAHZZWJKRGOISUJC
EKQKKPNEYCBWOQHTYFHHQZRLFNDOVXTWASSQWXKBIVTKTUIASK
PEKNJFIVBKOZUEPPHIWLUBFUDWPIDRJKAZVJKPBRHCRMGNMFWW
CGZAXHXPDELTACGUWBXWNNZNDQYYCIQRJCULIEBQBLLMJEUSZP
RWHHQMBIJWTQPUFNAESPZHAQARNIDUCRYQAZMNVRVZUJOZUDGS
PFGAYBDEECHUXFUZIKAXYDFWJNSAOPJYWUIEJSCORRBVQHCHMR
JNVIPVEMQSHCCAXMWEFSYIGFPIXNIDXOTXTNBCHSHUZGKXFECL
YZBAIIOTWLREPZISBGJLQDALKZUKEQMKLDIPXJEPENEIPWFDLP
HBQKWJFLSEXVILKYPNSWUZLDCRTAYUUPEITQJEITZRQMMAQNLN
DQDJGOWMBFKAIGWEAJOISPFPLULIWVVALLIIHBGEZLGRHRCKGF
LXYPCVPNUKSWCCGXEYTEBAWRLWDWNHHNNNWQNIIBUCGUJYMRYW
CZDKISKUSBPFHVGSAVJBDMNPSDKFRXVVPLVAQUGVUJEXSZFGFQ
IYIJGISUANRAXTGQLAVFMQTICKQAHLEBGHAVOVVPEXIMLFWIYI
ZIIFSOPCMAWCBPKWZBUQPQLGSNIBFADUUJJHPAIUVVNWNWKDZB
HGTEEIISFGIUEUOWXVTPJDVACYQYFQUCXOXOSSMXLZDQESHXKP
FEBZHJAGIFGXSMRDKGONGELOALLSYDVILRWAPXXBPOOSWZNEAS
VJGMAOFLGYIFLJTEKDNIWHJAABCASFMAKIENSYIZZSLRSUIPCJ
BMQGMPDRCPGWKTPLOTAINXZAAJWCPUJHPOUYWNWHZAKCDMZDSR
RRARTVHZYYCEDXJQNQAINQVDJCZCZLCQWQQIKUYMYMOVMNCBVY
ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXXdata = ["VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAG",\
"SDLLOVGRTWEYZKKXNKIRWGZWXWRHKXFASATDWZAPZRNHTNNGQF",\
"ZGUGXVQDQAEAHOQEADMWWXFBXECKAVIGPTKTTQFWSWPKRPSMGA",\
"BDGMGYHAOPPRRHKYZCMFZEDELCALTBSWNTAODXYVHQNDASUFRL",\
"YVYWQZUTEPFSFXLTZBMBQETXGXFUEBHGMJKBPNIHMYOELYZIKH",\
"ZYZHSLTCGNANNXTUJGBYKUOJMGOGRDPKEUGVHNZJZHDUNRERBU",\
"XFPTZKTPVQPJEMBHNTUBSMIYEGXNWQSBZMHMDRZZMJPZQTCWLR",\
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"MHJKFYYBQSDPOVJICWWGGCOZSBGLSOXOFDAADZYEOBKDDTMQPA",\
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"LXYPCVPNUKSWCCGXEYTEBAWRLWDWNHHNNNWQNIIBUCGUJYMRYW",\
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"IYIJGISUANRAXTGQLAVFMQTICKQAHLEBGHAVOVVPEXIMLFWIYI",\
"ZIIFSOPCMAWCBPKWZBUQPQLGSNIBFADUUJJHPAIUVVNWNWKDZB",\
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"FEBZHJAGIFGXSMRDKGONGELOALLSYDVILRWAPXXBPOOSWZNEAS",\
"VJGMAOFLGYIFLJTEKDNIWHJAABCASFMAKIENSYIZZSLRSUIPCJ",\
"BMQGMPDRCPGWKTPLOTAINXZAAJWCPUJHPOUYWNWHZAKCDMZDSR",\
"RRARTVHZYYCEDXJQNQAINQVDJCZCZLCQWQQIKUYMYMOVMNCBVY",\
"ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXX"]

ans = 0
for i in range(0,30):
for j in range(0,50):
for x in range(0,30):
for y in range(0,50):
if data[i][j] < data[x][y] and ((i == x and y > j) or (j == y and x > i) or (abs(y - j) == abs(x - i) and not (x <= i and y <= j))):
ans += 1
print(ans)

答案为52800

谢谢大家的支持,您的一键三连是 罡罡同学前进的最大动力!