Lua正则表达式模式如何匹配长尾词?

2026-03-31 22:411阅读0评论SEO资讯
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本文共计263个文字,预计阅读时间需要2分钟。

Lua正则表达式模式如何匹配长尾词?

我有这样一个URL字符串,需要从中匹配一些单词。例如:/school/student/studentname1/detail/55/address/address1我可以传递所需获取的细节,例如,local+s1,s2,s3=myString:match(/school/student/(.+)/detail/(.+)/address)

我有一个URL字符串,需要从匹配中获取某些单词.

例:

Lua正则表达式模式如何匹配长尾词?

/school/student/studentname1/detail/55/address/address1

我能够传递获取所需的细节,如,

local s1,s2,s3 =myString:match("/school/student/(.-)/detail/(.-)/address/(.-)")

现在的问题是我的字符串可以

myString = /school/student/studentname1

要么

myString = /school/student/studentname1/detail/55

在那种情况下,我的正则表达式失败,任何帮助?

local all_fields = { student = 1, detail = 2, address = 3 } local function parse(str) local info = {} local index for w in str:gmatch"/([^/]+)" do if index then info[index] = w index = nil else index = all_fields[w] end end return (table.unpack or unpack)(info, 1, 3) end local myString = '/school/student/studentname1/detail/55/address/address1' local s1, s2, s3 = parse(myString) print(s1, s2, s3) myString = '/school/student/studentname1/address/address1' s1, s2, s3 = parse(myString) print(s1, s2, s3) myString = '/school/student/studentname1/detail/55' s1, s2, s3 = parse(myString) print(s1, s2, s3)

本文共计263个文字,预计阅读时间需要2分钟。

Lua正则表达式模式如何匹配长尾词?

我有这样一个URL字符串,需要从中匹配一些单词。例如:/school/student/studentname1/detail/55/address/address1我可以传递所需获取的细节,例如,local+s1,s2,s3=myString:match(/school/student/(.+)/detail/(.+)/address)

我有一个URL字符串,需要从匹配中获取某些单词.

例:

Lua正则表达式模式如何匹配长尾词?

/school/student/studentname1/detail/55/address/address1

我能够传递获取所需的细节,如,

local s1,s2,s3 =myString:match("/school/student/(.-)/detail/(.-)/address/(.-)")

现在的问题是我的字符串可以

myString = /school/student/studentname1

要么

myString = /school/student/studentname1/detail/55

在那种情况下,我的正则表达式失败,任何帮助?

local all_fields = { student = 1, detail = 2, address = 3 } local function parse(str) local info = {} local index for w in str:gmatch"/([^/]+)" do if index then info[index] = w index = nil else index = all_fields[w] end end return (table.unpack or unpack)(info, 1, 3) end local myString = '/school/student/studentname1/detail/55/address/address1' local s1, s2, s3 = parse(myString) print(s1, s2, s3) myString = '/school/student/studentname1/address/address1' s1, s2, s3 = parse(myString) print(s1, s2, s3) myString = '/school/student/studentname1/detail/55' s1, s2, s3 = parse(myString) print(s1, s2, s3)