如何用C语言编写程序将直角坐标转换为极坐标？

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本文实例讲述了C语言实现直角坐标转换成极坐标的方法。分享给广大读者，供大家参考。具体如下：

c#include #include

// 直角坐标转极坐标函数void convertToPolar(double x, double y, double *r, double *theta) { *r=sqrt(x * x + y * y); // 计算极径 *theta=atan2(y, x); // 计算极角}

int main() { double x, y, r, theta;

// 输入直角坐标 printf(请输入直角坐标(x, y): ); scanf(%lf %lf, &x, &y);

// 调用转换函数 convertToPolar(x, y, &r, &theta);

// 输出极坐标 printf(极坐标为: (r, theta)=(%.2f, %.2f)\n, r, theta);

return 0;}

本文实例讲述了C语言实现直角坐标转换为极坐标的方法。分享给大家供大家参考，具体如下：

#include<stdio.h> #include<math.h> struct complex_s{ double x,y; }; double real_part(struct complex_s z){ return z.x; } double img_part(struct complex_s z){ return z.y; } double magnitude(struct complex_s z){ return sqrt(z.x*z.x + z.y*z.y); } double angle(struct complex_s z){ return atan2(z.y, z.x); } struct complex_s make_from_real_img(double x, double y){ struct complex_s z; z.x = x; z.y = y; return z; } struct complex_s make_from_mag_ang(double r, double A){ struct complex_s z; z.x = r * cos(A); z.y = r * sin(A); return z; } struct complex_s add_complex(struct complex_s z1,struct complex_s z2){ return make_from_real_img(real_part(z1)+real_part(z2), img_part(z1) + img_part(z2)); } struct complex_s sub_complex(struct complex_s z1,struct complex_s z2){ return make_from_real_img(real_part(z1)-real_part(z2), img_part(z1) - img_part(z2)); } struct complex_s mul_complex(struct complex_s z1,struct complex_s z2){ return make_from_mag_ang(real_part(z1)*real_part(z2), img_part(z1) + img_part(z2)); } struct complex_s div_complex(struct complex_s z1,struct complex_s z2){ return make_from_mag_ang(real_part(z1)/real_part(z2), img_part(z1) + img_part(z2)); } int main(void){ struct complex_s z1 = {3.0,4.0}; struct complex_s z2= {2.0,5.0}; struct complex_s x; x = add_complex(z1,z2); printf("x={%f,%f}",x.x,x.y); return 0; }

结果：

[root@localhost struct]# ./jizuobiao.out x={5.000000,9.000000}

希望本文所述对大家C语言程序设计有所帮助。