如何使用Python上传文件并保存为临时文件,进而以CSV和XLS格式进行读取?
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本文共计183个文字,预计阅读时间需要1分钟。
1. 上传并保存临时文件pythonasync def upload(file: UploadFile): file_name=file.filename file_suffix=file.filename.split(.)[1] cur_path=os.path.abspath('.')
1. UPload上传保存临时文件
async def upload(file: UploadFile = File(...)):file_name = file.filename.split(".")[0]
file_suffix = file.filename.split(".")[1]
cur_path = os.path.abspath('.') + os.sep + "upload" + os.sep
full_path = cur_path + file_name + "_file"
# 保存文件
with open(full_path, 'wb') as fw:
res = await file.read()
fw.write(res)
context = {"status": 200, "msg": "success"}
return
2. 读取csv
import csvdef read_csv(full_path):
with codecs.open(full_path, 'r', 'gbk', errors='ignore') as fw:
lines = csv.reader(fr)
for line in lines:
print(line)
3. 读取xls
import xlrddef read_xls(full_path):
wb = xlrd.open_workbook(full_path)
sheet = wb.sheet_by_index(0) # 获取第一个sheet表数据
for raw in range(1, sheet.nrows - 1):
lines = sheet.row_values(raw)
print(lines)
本文共计183个文字,预计阅读时间需要1分钟。
1. 上传并保存临时文件pythonasync def upload(file: UploadFile): file_name=file.filename file_suffix=file.filename.split(.)[1] cur_path=os.path.abspath('.')
1. UPload上传保存临时文件
async def upload(file: UploadFile = File(...)):file_name = file.filename.split(".")[0]
file_suffix = file.filename.split(".")[1]
cur_path = os.path.abspath('.') + os.sep + "upload" + os.sep
full_path = cur_path + file_name + "_file"
# 保存文件
with open(full_path, 'wb') as fw:
res = await file.read()
fw.write(res)
context = {"status": 200, "msg": "success"}
return
2. 读取csv
import csvdef read_csv(full_path):
with codecs.open(full_path, 'r', 'gbk', errors='ignore') as fw:
lines = csv.reader(fr)
for line in lines:
print(line)
3. 读取xls
import xlrddef read_xls(full_path):
wb = xlrd.open_workbook(full_path)
sheet = wb.sheet_by_index(0) # 获取第一个sheet表数据
for raw in range(1, sheet.nrows - 1):
lines = sheet.row_values(raw)
print(lines)

