很抱歉，您没有提供需要改写的句子。请提供您希望改写的句子，我将为您改写为一个长尾词的。

本文共计242个文字，预计阅读时间需要1分钟。

如何使用不同作用域和名称空间，以及`global`和`nonlocal`对变量绑定的影響：

pythondef scope_test(): def do_local(): spam=local spam

def do_nonlocal(): nonlocal spam spam=nonlocal spam

spam=global spam do_local() do_nonlocal() print(spam)

如何引用不同作用域和名称空间，以及​​global​​和​​nonlocal​对变量绑定的影响：

def scope_test():
def do_local():
spam = "local spam"

def do_nonlocal():
nonlocal spam
spam = "nonlocal spam"

def do_global():
global spam
spam = "global spam"

spam = "test spam"
do_local()
print("After local assignment:", spam)
do_nonlocal()
print("After nonlocal assignment:", spam)
do_global()
print("After global assignment:", spam)

scope_test()
print("In global scope:", spam)

示例代码的输出是：

After local assignment: test spam
After nonlocal assignment: nonlocal spam
After global assignment: nonlocal spam
In global scope: global spam

注意，局部赋值（这是默认状态）不会改变​scope_test​对​spam​的绑定。nonlocal赋值会改变​scope_test​对​spam​的绑定，而global赋值会改变模块层级的绑定。

而且，global赋值前没有​spam​的绑定。