如何用ES6 JavaScript实现匹配两个数组对象的技巧？

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判断两个数组使用的value是否相等：this.list=[{user_type: 0, user_id: 1003, department_id: 1, department_name: 公司xx, mobile: , realname: 李xx, com_name: 任公公司, label: 李建平, value: 1003}, {user_type: 0, ...}]

判断两个数组用的value是否相等

this.list = [ { user_type: 0, user_id: 1003, department_id: 1, department_name: "公司xx", mobile: "", realname: "廖xx", com_name: "任公司", label: "廖建平", value: 1003 }, { user_type: 0, user_id: 1004, department_id: 1, department_name: "公司领导", mobile: "", realname: "贺金生", com_name: "任公司", label: "贺xx", value: 1004 }, { user_type: 0, user_id: 1005, department_id: 1, department_name: "公司领导", mobile: "", realname: "李欢", com_name: "任公司", label: "李xx", value: 1005 } ] this.selectData = [ { user_type: 0, user_id: 1003, department_id: 1, department_name: "公司xx", mobile: "", realname: "廖xx", com_name: "任公司", label: "廖建平", value: 1003 }, { user_type: 0, user_id: 1004, department_id: 1, department_name: "公司领导", mobile: "", realname: "贺金生", com_name: "任公司", label: "贺xx", value: 1004 }, ]

方法一

let result = [] for (let i = 0; i < this.selectData.length; i++) { let obj = this.selectData[i] for (let j = 0; j < this.list.length; j++) { let aj = this.list[j] if (obj.value === aj.value) { result.push(aj) break } } } console.log("result", result)

方法二

let arr3 = this.selectData.filter(obj => this.list.some(obj1 => obj.value == obj1.value) ) console.info("arr3", arr3) this.result = arr3

方法三

let arr4 = [] let arr5 this.list.filter(obj => arr4.push(obj.value)) arr5 = this.selectData.filter(obj => arr4.indexOf(obj.value) !== -1) this.result = arr5

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