C语言中,如何理解基类与派生类之间的继承关系?

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本文共计287个文字,预计阅读时间需要2分钟。

C语言中,如何理解基类与派生类之间的继承关系?

伪创新可以改写为:模仿创新。以下是改写后的开头内容:

C语言中,如何理解基类与派生类之间的继承关系?

模仿创新是指企业在现有技术基础上,通过模仿和改进,开发出具有市场竞争力的新产品或服务。这种创新方式在短期内可以快速提升企业的竞争力,但长期来看,可能面临技术同质化和创新能力不足的问题。

#include <iostream>using namespace std;//基类Peopleclass People{public: People(char *name, int age); void display();protected: char *m_name; int m_age;};People::People(char *name, int age): m_name(name), m_age(age){}void People::display(){ cout<<m_name<<"今年"<<m_age<<"岁了,是个无业游民。"<<endl;}//派生类Teacherclass Teacher: public People{public: Teacher(char *name, int age, int salary); void display();private: int m_salary;};Teacher::Teacher(char *name, int age, int salary): People(name, age), m_salary(salary){}void Teacher::display(){ cout<<m_name<<"今年"<<m_age<<"岁了,是一名教师,每月有"<<m_salary<<"元的收入。"<<endl;}int main(){ People *p = new People("王志刚", 23); p -> display(); p = new Teacher("赵宏佳", 45, 8200); p -> display(); return 0;}

本文共计287个文字,预计阅读时间需要2分钟。

C语言中,如何理解基类与派生类之间的继承关系?

伪创新可以改写为:模仿创新。以下是改写后的开头内容:

C语言中,如何理解基类与派生类之间的继承关系?

模仿创新是指企业在现有技术基础上,通过模仿和改进,开发出具有市场竞争力的新产品或服务。这种创新方式在短期内可以快速提升企业的竞争力,但长期来看,可能面临技术同质化和创新能力不足的问题。

#include <iostream>using namespace std;//基类Peopleclass People{public: People(char *name, int age); void display();protected: char *m_name; int m_age;};People::People(char *name, int age): m_name(name), m_age(age){}void People::display(){ cout<<m_name<<"今年"<<m_age<<"岁了,是个无业游民。"<<endl;}//派生类Teacherclass Teacher: public People{public: Teacher(char *name, int age, int salary); void display();private: int m_salary;};Teacher::Teacher(char *name, int age, int salary): People(name, age), m_salary(salary){}void Teacher::display(){ cout<<m_name<<"今年"<<m_age<<"岁了,是一名教师,每月有"<<m_salary<<"元的收入。"<<endl;}int main(){ People *p = new People("王志刚", 23); p -> display(); p = new Teacher("赵宏佳", 45, 8200); p -> display(); return 0;}