Python示例5：如何实现表格数据的打印？

本文共计402个文字，预计阅读时间需要2分钟。

pythondef printTable(table): # 获取表头 headers=table[0] # 获取列宽 col_widths=[max(len(str(item)) for item in col) for col in zip(*table)] # 输出表头 print(' | '.join(header.ljust(col_width) for header, col_width in zip(headers, col_widths))) # 输出分隔线 print('-' * (sum(col_widths) + len(col_widths) - 1)) # 输出表格内容 for row in table[1:]: print(' | '.join(str(item).ljust(col_width) for item, col_width in zip(row, col_widths)))

编写一个名为printTable()的函数，它接受字符串的列表的列表，将它显示在组织良好的表格中，每列右对齐。假定所有内层列表都包含同样数目的字符串。例如，该值可能看起来像这样：

table_data = [[‘apples‘, ‘oranges‘, ‘cherries‘, ‘banana‘], [‘Alice‘, ‘Bob‘, ‘Carol‘, ‘David‘], [‘dogs‘, ‘cats‘, ‘moose‘, ‘goose‘]]

你的 printTable()函数将打印出：

apples Alice dogs oranges Bob cats cherries Carol moose banana David goose　　

示例代码1：

import copy def count_width(the_list): new_list = copy.deepcopy(the_list) col_widths = [0]*len(the_list) i = 0 while i < len(new_list): new_list[i].sort(key=lambda x: len(x), reverse=True) col_widths[i] = new_list[i][0] i = i+1 return col_widths def list_ljust(the_list): widths = count_width(the_list) for j in range(len(the_list[0])): for i in range(len(the_list)): print(the_list[i][j].ljust(len(widths[i])), end=‘ ‘) print(‘\r‘) table_data = [[‘apples‘, ‘oranges‘, ‘cherries‘, ‘banana‘], [‘Alice‘, ‘Bob‘, ‘Carol‘, ‘David‘], [‘dogs‘, ‘cats‘, ‘moose‘, ‘goose‘]] list_ljust(table_data)　　

sort方法：

lambda函数：

示例代码2：

def count_widths(the_list): col_widths = [0]*len(the_list) for i in range(len(the_list)): for j in range(len(the_list[0])): if len(the_list[i][j]) > max_len: max_len = len(the_list[i][j]) col_widths[i] = max_len return col_widths def list_ljust(the_list): widths = count_widths(the_list) print(widths) for j in range(len(the_list[0])): for i in range(len(the_list)): print(the_list[i][j].ljust(widths[i]), end=‘ ‘) print(‘\r‘) table_data = [[‘apples‘, ‘oranges‘, ‘cherries‘, ‘banana‘], [‘Alice‘, ‘Bob‘, ‘Carol‘, ‘David‘], [‘dogs‘, ‘cats‘, ‘moose‘, ‘goose‘]] list_ljust(table_data)