如何用PHP计算任意两点经纬度间的具体距离?

2026-04-05 06:028阅读0评论SEO资讯
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本文共计149个文字,预计阅读时间需要1分钟。

如何用PHP计算任意两点经纬度间的具体距离?

javascriptfunction getDistanceBetweenPoints(latitude1, longitude1, latitude2, longitude2) { var theta=longitude1 - longitude2; var miles=Math.acos(Math.sin(deg2rad(latitude1)) * Math.sin(deg2rad(latitude2)) + Math.cos(deg2rad(latitude1)) * Math.cos(deg2rad(latitude2)) * Math.cos(deg2rad(theta))); return miles;}

如何用PHP计算任意两点经纬度间的具体距离?

function getDistanceBetweenPointsNew($latitude1, $longitude1, $latitude2, $longitude2) { $theta = $longitude1 - $longitude2; $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta))); $miles = acos($miles); $miles = rad2deg($miles); $miles = $miles * 60 * 1.1515; $feet = $miles * 5280; $yards = $feet / 3; $kilometers = $miles * 1.609344; $meters = $kilometers * 1000; return compact('miles','feet','yards','kilometers','meters'); }
用法:

<?php $point1 = array('lat' => 40.770623, 'long' => -73.964367); $point2 = array('lat' => 40.758224, 'long' => -73.917404); $distance = getDistanceBetweenPointsNew($point1['lat'], $point1['long'], $point2['lat'], $point2['long']); foreach ($distance as $unit => $value) { echo $unit.': '.number_format($value,4).'<br />'; } ?>

本文共计149个文字,预计阅读时间需要1分钟。

如何用PHP计算任意两点经纬度间的具体距离?

javascriptfunction getDistanceBetweenPoints(latitude1, longitude1, latitude2, longitude2) { var theta=longitude1 - longitude2; var miles=Math.acos(Math.sin(deg2rad(latitude1)) * Math.sin(deg2rad(latitude2)) + Math.cos(deg2rad(latitude1)) * Math.cos(deg2rad(latitude2)) * Math.cos(deg2rad(theta))); return miles;}

如何用PHP计算任意两点经纬度间的具体距离?

function getDistanceBetweenPointsNew($latitude1, $longitude1, $latitude2, $longitude2) { $theta = $longitude1 - $longitude2; $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta))); $miles = acos($miles); $miles = rad2deg($miles); $miles = $miles * 60 * 1.1515; $feet = $miles * 5280; $yards = $feet / 3; $kilometers = $miles * 1.609344; $meters = $kilometers * 1000; return compact('miles','feet','yards','kilometers','meters'); }
用法:

<?php $point1 = array('lat' => 40.770623, 'long' => -73.964367); $point2 = array('lat' => 40.758224, 'long' => -73.917404); $distance = getDistanceBetweenPointsNew($point1['lat'], $point1['long'], $point2['lat'], $point2['long']); foreach ($distance as $unit => $value) { echo $unit.': '.number_format($value,4).'<br />'; } ?>