哪个对象的权重最高，以该属性为key，是长尾词？

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分析是否存在重复获奖用户，并获取最高奖励的奖励详情：奖励Map rewardMap=new HashMap(3); ActivityNovReward[] rewardArray={firstReward, lastReward, maxReward}; ActivityNovReward activityNovReward

gistfile1.txt

// 三个奖励是否为存在重复获奖用户， 有则取最高奖励的那个奖励 Map rewardMap = new HashMap (3); ActivityNovReward[] rewardArray = {firstReward,lastReward,maxReward}; ActivityNovReward activityNovReward = null ; for(ActivityNovReward reward :rewardArray ){ if(reward == null){ continue; } activityNovReward = rewardMap.get(reward.getUserId()); if(activityNovReward != null){ //存在重复奖励， reward 和 activityNovReward 的用户id 是一样的 if(reward.getRewardAmt().compareTo(activityNovReward.getRewardAmt()) == 1){ // reward 奖励 大于 activityNovReward , 用户 reward 覆盖掉 activityNovReward rewardMap.put(reward.getUserId(), reward); } }else{ rewardMap.put(reward.getUserId(), reward); } }